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Glucose
Synthesis and Reactions
| As you have learned, glucose can be synthesized from water and carbon
dioxide by a process known as photosynthesis. However, that's not the
only way in which glucose can be created. It can also be synthesized from pyruvic
acid and acetyl CoA by reversing the reactions that we studied
earlier in the oxidation of glucose. Consequently, glucose can be made from such things as
fats, carboxylic acids, and also amino acids
by first converting them into acetyl CoA or pyruvic acid. (This diagram is also shown in
Example 13 in your workbook.) |
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In turn, glucose can be used as a starting material to make fats, carboxylic acids and
amino acids, and other chemicals.
| Glucose can also be converted into a variety of other sugar molecules by
doing such things as reorienting the location of hydroxyl groups, such as when it is
converted into galactose, or by oxidizing one carbon and reducing another
by shifting the locations of the hydrogen atoms, such as when it is converted into fructose. |
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D- or L- Designation
The bonding pattern of the hydrogens and hydroxyl groups around each carbon atom is
very important to the structure of carbohydrates. You should recall that a carbon atom
which is bonded to four different groups is an asymmetric carbon atom.
| Glucose, with six carbon atoms, has four asymmetric carbon atoms (marked
in this diagram with *). The arrangement of the OH's and H's on these atoms is very
important. Structural formulas for sugar molecules are often written in this vertical
arrangement with the aldehyde or the ketone group at or near the top. When written in this
particular way, the position of the OH on the last asymmetric carbon atom will tell us
whether we are dealing with a "D" sugar or an "L" sugar. "D"
stands for dextro and "L" stands for levo. If the OH is on the right, then we
are dealing with a "D" sugar, in this case D-glucose. |
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| Each of these sugars is a "D" sugar because the OH on the last
asymmetric carbon atom is written on the right. Therefore, D-galactose, D-glucose, and
D-fructose. Had the OH group attached to the last asymmetric carbon atom been on the left,
then these would have been "L" sugars. When you see D's and L's in front of the
names of carbohydrates, this is the reason for it. |
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Left-Right Orientation of OH Groups
| When you look at the model for a particular saccharide and compare it to a
structural formula, there may not seem to be much relationship as regards the location of
the OH's. In part, this is because the structural formula is written in two dimensions and
the models are in three dimensions. The formulas have four simple directions - up, down,
left, right. With models you have the directions of the tetrahedral arrangements of the
bonds around the carbon atoms. |
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| When deciding whether a hydroxyl group is on the right side or the left
side of the carbon atom in a model, you must arrange the model in such a way as to have
the lower numbered carbon at the top and the next higher numbered carbon below the one
that you're looking at and have this carbon closer to you than either the preceding or
following carbon. In this diagram the bonds on the second carbon atom are wedged (wide end
toward you) to give the impression that the second carbon is closer to you than the first
or third. |
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| You can see the same thing here in the hand held model. The OH on the
second carbon is on the right when the molecule is held in this position. Note that in the
model the rest of the molecule is not nearly so orderly as in the diagram. That is one of
the advantages of such diagrams, they are more orderly than what they are representing.
The advantage here is that the diagram systematically represents the locations of the H
and OH groups. The disadvantage is that it does not represent the true shape of the
molecule. For that reason, different diagrams are used to represent different aspects of
sugar molecules. |
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| When we go to the third carbon atom, keeping it closer to us than the
second and fourth, you can see that the OH is on the left. |
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| When we look at the fourth carbon atom, still making sure that it's closer
to us than the third or the fifth carbon atoms, you can see that the OH is on the right
side. |
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| Going on to the fifth carbon, which is the last asymmetric carbon atom,
the OH is also on the right. That is what makes this molecule of glucose a "D"
molecule, D-glucose. |
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We don't need to worry about the position of the OH on the sixth carbon atom, because
it is is not an asymmetric carbon. It really doesn't matter whether it's drawn left or
right, bond rotation and having two hydrogens on the carbon atom make that irrelevant.
When you are in the lab, be sure to work with the models to get familiar with these
aspects of the structure of glucose molecules. One thing you should be sure to note is
that the shapes of the molecules are flexible even though the representation on paper is
quite rigid.
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E-mail instructor:
Sue Eggling
Clackamas Community College
©2001, 2003 Clackamas Community College, Hal Bender
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