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Citric Acid Cycle
In order for you to become more familiar with
what happens to chemicals in the citric acid cycle, I would like you to do
exercise 5 now. In doing that, you will be looking at different versions of the
citric acid cycle and selecting the one which allows you to best figure
out what kinds of changes are taking place. (Note that
if you have done lesson 6, you should use the citric acid cycle diagram that you
prepared in that lesson.) Otherwise,
draw out a diagram labeling the reactions for
each step in the cycle. Please take some time
now to do that and then we will continue with the lesson.
Overall Cycle
| Here is the version of the
citric acid cycle that I'm going to be working with (Ex. 6), and as I talk
about the steps that are involved in this process, I'd like you to go
through on your own version and make sure that you noted some of the same
changes. |
![Citric acid cycle - structural formulas of all components, with citric acid labeled. [cacall1.jpg]](images/cacall1.jpg)
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Getting Started
| Let's start with citric acid and work from there. It is quite common for textbooks to work
with the ionic form of this compound, so the version that you have in front of you may
very well refer to citrate rather than citric acid, and if that's the
case, three hydrogen atoms would have been removed and it would be an ionic compound. |
![Structure of citric acid. [cac00.jpg]](images/cac00.jpg)
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| It's also quite common for textbooks to take these first two steps and
treat them as one. They go from citric acid (or citrate) to isocitric
acid (or isocitrate) and call it an isomerization reaction. But
I'll break it down into two smaller steps. |
![Equation for steps 1 and 2 in the citric acid cycle. [cac0102a.jpg]](images/cac0102a.jpg)
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Step 1
| Going from citric acid to the next compound, you should notice that we
have the same network of carbon atoms. The change that occurs is that a double bond
appears and an -OH and an -H disappear. So this first
step is essentially a dehydration reaction. |
![Equation for the reaction in step 1 of the citric acid cycle. [cac01a.jpg]](images/cac01a.jpg)
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Step 2
| In the next step, the double bond disappears and an -OH
and an -H reappear. So this step is an addition
reaction. The water molecule has been added back in. But note that the -OH is in a
different position than it was in citric acid. This compound is an isomer of citric acid
(and thus it is named isocitric acid). |
![Equation for the reaction in step 2 of the citric acid cycle. [cac02a.jpg]](images/cac02a.jpg)
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| Again, if the version that you were working with showed the reaction going
directly from the first compound to the third, you would classify that as an isomerization
reaction. One in which the hydrogen and the hydroxyl groups change place. |

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Step 3
| As we go to the next step in this process, the change is that two hydrogen
atoms and their electrons are removed. So this, of course, is an oxidation
reaction. |
![Equation for the reaction in step 3 of the citric acid cycle. [cac03a.jpg]](images/cac03a.jpg)
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Step 4
| In the next step a carbon atom and two oxygen atoms disappear. A carbon
dioxide molecule has been removed and this is called a decarboxylation
reaction. |
![Equation for the reaction in step 4 of the citric acid cycle. [cac04a.jpg]](images/cac04a.jpg)
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Step 5
| The next step is a bit of a challenge. One carbon atom, two oxygen atoms
and one hydrogen atom have been removed. That amounts to removing a CO2 molecule
and one hydrogen with its electron. We have also added the coenzyme A. Remember that
the coenzyme A starts out with a hydrogen (as CoASH). That hydrogen is
removed when coenzyme A attaches to this molecule. So we've actually released two hydrogen
atoms with their electrons. |
![Equation for the reaction in step 5 of the citric acid cycle. [cac05a.jpg]](images/cac05a.jpg)
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Step 6
| In the next step we've removed the coenzyme A and we've put in an -OH.
When the coenzyme A is set free it requires a hydrogen atom to go with it. So this is a hydrolysis
reaction in which the -OH goes to the carbon and the -H
goes to the coenzyme A. |
![Equation for the reaction in step 6 of the citric acid cycle. [cac06a.jpg]](images/cac06a.jpg)
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Step 7
| In this next step a double bond appears in the middle of the molecule as a
result of the removal of two hydrogen atoms along with their electrons. This is another oxidation
reaction. |
![Equation for the reaction in step 7 of the citric acid cycle. [cac07a.jpg]](images/cac07a.jpg)
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Step 8
| In this step the double bond disappears and an H- and -OH
have appeared, so this reaction is an addition of water. |
![Equation for the reaction in step 8 of the citric acid cycle. [cac08a.jpg]](images/cac08a.jpg)
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Step 9
| The next step involves removing two hydrogen atoms and their electrons, so we
have another oxidation reaction. |
![Equation for the reaction in step 9 of the citric acid cycle. [cac09a.jpg]](images/cac09a.jpg)
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Step 10
Now we get to the step that involves regenerating the citric acid from this compound,
which is called oxaloacetic acid. This step is somewhat involved, so I will describe it
twice. First will be a deduction of what appears to happen based on the formulas of the
chemicals involved. This is what I expect you may have been able to deduce. Following that
will be a more complete description of how the reaction is accomplished.
| In order to change the first molecule into the second, a number of things
have to happen. First of all, we start with four carbon atoms and end with six. So we must
somehow have to add two carbon atoms, along with other atoms. It would
seem that could be accomplished by an addition reaction across the circled C=O
double bond using an acetic acid molecule (in red). In these diagrams the
orientation of one -COOH group (circled in green) has been changed, as
has the orientation of the C=O group (circled in red) that becomes a C-OH
group. |
![Equation for the reaction in step 10 of the citric acid cycle. [cac10a.jpg]](images/cac10a.jpg)
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However, an acetic acid molecule, as such, is not involved in this reaction. Instead,
those new atoms will come from the acetyl CoA that is generated from the
breakdown of fat molecules. The diagram below gives a more complete description of what
happens.
| It will be easier to see how the new atoms fit in if we reorient the
oxaloacetic acid molecule, moving the oxygen in the carbonyl group (C=O)
from the right side of the molecule to the left and moving the lower -COOH
up and to the right. Now the acetyl CoA can add across the C=O
double bond (circled in red) and attach at the bottom of the molecule. The oxygen gains a
hydrogen and the carbon gains the rest of the acetyl CoA. |
![Equation for the reaction in step 10 of the citric acid cycle with extra annotation. [cac10xa.jpg]](images/cac10xa.jpg)
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| Then the coenzyme A is released by a hydrolysis
reaction in which a water molecule provides an -OH to
make the citric acid complete. It also provides the -H needed to complete
the coenzyme A. |
Note that what is shown as one step in the overall diagram really involves several
things happening in quick succession.
Overall
| As you take a look at this overall process, keep in mind what you are
and what you are not responsible for remembering about the citric acid
cycle. |
![Equations for the reactions in the citric acid cycle. [cacall2.jpg]](images/cacall2.jpg)
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You are not going to be held responsible for knowing what all the steps are in the
citric acid cycle. Even so, you do need to know several things.
 | This process does involve many steps. |
 | By looking at each step, you should be able to figure out what kind of reaction
each one is. |
 | You should know how the citric acid cycle fits into the overall scheme of things,
specifically the overall process of oxidizing fats to form carbon dioxide and water.
 | You need to know that glucose is broken down into smaller molecules. |
 | Those are changed in turn to acetyl CoA which feeds into the citric acid cycle creating
a citric acid molecule. |
 | That citric acid molecule undergoes quite a number of changes and those changes involve
giving off carbon dioxide at two points and giving off pairs of hydrogen atoms with
electrons at four points. |
 | The hydrogen that is released combines with oxygen that we have
breathed in, so that we then breathe out water vapor and carbon dioxide. |
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So far, you have seen how carbon dioxide is formed, but you have not yet seen how the
hydrogen is joined with oxygen to become water. That involves the electron
transport system, which is the next section of this lesson.
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E-mail instructor:
Sue Eggling
Clackamas Community College
©2001, 2003 Clackamas Community College, Hal Bender
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